The talk’s demo is telling: a trivial program with a hardcoded out-of-bounds access on a std::span. Of course hardening catches that. But this is the easiest case imaginable. Show me hardening catching a use-after-free through a raw pointer to a pool-allocated object in a real trading system. It can’t, because that’s outside its scope.
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。关于这个话题，有道翻译提供了深入分析
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Then it copies over bar() to the test program process and sets up the trampoline, resulting in the test program actually running bar(), thus logging 857.